$\Delta Q = m C \Delta T$, $\Delta u = nC_v \Delta T$ and $\Delta W = P \Delta V$

Now, at constant pressure P, $V \propto T \rightarrow \large\frac{\Delta T}{T} $$= 20\text{%}$

$\Rightarrow T_{\text{final}} = 327.5 ^{\circ} K \rightarrow \Delta T = 54.6 ^{\circ}$

Also, $m = 64\;g \rightarrow \Delta Q = 64 \times 0.22 \times 54.6 \approx 768\; \text{cal}$