Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
0 votes

A student while performing an experiment forgot to add the reaction mixture and started heating the open round bottom flask on the flame. If he found the temperature to be $227 ^{\circ} C$ after heating, which was $27 ^{\circ} C$ earlier, what fraction of air would have been expelled out?

(A) $\large\frac{2}{5}$ (B) $\large\frac{4}{5}$ (C) $\large\frac{3}{5}$ (D) $\large\frac{1}{5}$
Can you answer this question?

1 Answer

0 votes
For an open vessel containing gas inside, pressure and volume corresponding to the gas remains the same.
So $nT = $ constant for the gas inside.
Therefore $n_1 T_1 = n_2 T_2$
$\Rightarrow n_1 (273+27) = n_2 (227+23) \rightarrow 300 n_1 = 500 n_2 \rightarrow n_2 = \large\frac{3}{5} $$n_1$
So, 60% of the original amount of air is still there. Therefore the fraction of air expelled is two-fifths, $\large\frac{2}{5}$.
answered Mar 11, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App