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# The density of the gaseous mixture of Hydrogen and Carbon-di-Oxide is $\large\frac{30\;g}{22.4\;l}$ at NTP. What is the % composition of Hydrogen and Carbon-di-oxide by volume in the mixture respectively?

(A) 33.3, 66.7 (B) 50, 50 (C) 66.7, 33.3 (D) 40, 60

Toolbox:
• Density of a gas mixture can be calculated as: $ρm = (ρ1 v1 + ρ2 v2 + .. + ρn vn) / (v1 + v2 + .. + vn )$
• Molecular weight of Hydrogen = 2 and that of Carbon-di-oxide = 44.
Given: The density of the gaseous mixture of Hydrogen and Carbon-di-Oxide is $\large\frac{30\;g}{22.4\;l}$ at NTP
Let $x$ be the percent composition of Hydrogen.
Molar mass of mixture of $22.4\;l$ is $30g$, therefore:
$30 = \large\frac{x\times 2 + (100-x) \times 44}{100}$
$\Rightarrow$ solving for $x, x = \large\frac{1400}{44}$$= 33.33\text{%} \rightarrow 100 - x = 66.66\text{%}$