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# If ideal gas is taken through a process given by the graph below, identify which of the following options is incorrect:

(A) From 1 -> 2 Pressure will Decrease (B) From 1 -> 2 pressure will Increase (C) From 2 -> 3 Pressure remains the same (D) Pressure at 3 is greater than Pressure at 1

For an ideal gas, $PV = nRT$.
From $1 -> 2, V + T =$ constant (say $k$) (from the graph)..
So, $P (k - T) = nRT \rightarrow P = \large\frac{nRT}{k-T}$
As $T$ increases, $k-T$ decreases and $P$ increases.
From $2 -> 3, V = k' T (k' \gt 0) \rightarrow P (k'T) = nRT \rightarrow P =$ constant.