logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The electron configuration of Actinides are gives as

$ (a)\;(4f)^{1-14}(5d)^{0-1} (6S)^2 \\(b)\;(4f)^{1-13}(5d)^{0-1}(7S)^2 \\ (c)\;(5f)^{1-14}(6d)^{0-1}(7s)^2 \\ (d)\;(5f)^{0-1}(6d)^{1-14}(7s)^2 $

Can you answer this question?
 
 

1 Answer

0 votes
$ (5f)^{1-14}(6d)^{0-1}(7s)^2 $ is correct answer.
Hence c is the correct answer.
answered Mar 12, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...