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The electron configuration of Actinides are gives as

$ (a)\;(4f)^{1-14}(5d)^{0-1} (6S)^2 \\(b)\;(4f)^{1-13}(5d)^{0-1}(7S)^2 \\ (c)\;(5f)^{1-14}(6d)^{0-1}(7s)^2 \\ (d)\;(5f)^{0-1}(6d)^{1-14}(7s)^2 $

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1 Answer

$ (5f)^{1-14}(6d)^{0-1}(7s)^2 $ is correct answer.
Hence c is the correct answer.
answered Mar 12, 2014 by meena.p
 

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