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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Polymers
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The arrangements of the following polymers in increasing order of their intermolecular forces is

$\begin{array}{1 1}(a)\;\text{Polythene < Nylon-66 < Buna-S}\\(b)\; \text{Buna-S < Polythene < Nylon-66}\\(c)\;\text{ Polythene < Buns-S < Nylon-66}\\(d)\;\text{Nylon-66 < Buna-S < Polythene}\end{array}$

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Nylon-66 is a condensation polymer.Buna-S and polythene are addition polymer.
On the basis of intermolecular forces:-
Elastomers(Buna-S) < Thermoplastics(polythene) < fibres(Nylon-66) < Thermosetting
Hence (b) is the correct answer.
answered Mar 12, 2014 by sreemathi.v
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