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# Ram is pedaling his bicylce down a road, perpendicular to the Earth's magnetic field of $5.5 \times 10^{-5} T$. His Wheel has an area of $1.2 m^2$. What is the flux through the metal rim of his bicycle wheel?

(A) $6.6 \times 10^{-5} Wb$ (B) $6.2 \times 10^{-5} Wb$ (C) $5.6 \times 10^{-5} Wb$ (D) $6.4 \times 10^{-5} Wb$

Given $A = 1.2 m^2$ and $B = 5.5 \times 10^{-5} T$, we need to find $\Phi$
$\Phi = AB = 1.2 m^2 \times 5.5 \times 10^{-5} = 6.6 \times 10^{-5} Wb$