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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

From a rectangular box , a circular portion is removed and the figure looks like - when the object is heated , the distance PQ -

$(a)\;increases\qquad(b)\;decreases\qquad(c)\;depends\;on\;temperature\qquad(d)\;data\;insufficient$

1 Answer

Answer : increases
Explanation :
Had there been the circular part , the ponits P & Q must have been separated . So , removing the portion has no special effect . So, PQ distance increases .
answered Mar 12, 2014 by yamini.v
edited Mar 13, 2014 by yamini.v
 

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