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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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Q)

A ball is dropped from a height of $10\; m$ & it rises to a height of $5\; m$ . Assuming $\;50 \%\;$ of the energy goes into increasing temperature of ball , the temperature rise is (specific heat of ball's material = $\;1000 JK^{-1}$)

$(a)\;10^{-3} \times 100^{\circ}C\qquad(b)\;10^{-3} \times 50^{\circ}C\qquad(c)\;{10^{-3}}^{\circ}C\qquad(d)\;10^{-2} \times 50^{\circ}C$

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