$(a)\;5.4 \times 10^{3}\;cal\qquad(b)\;0.5 \times 10^{3}\;cal\qquad(c)\;4.9 \times 10^{3}\;cal\qquad(d)\;5.9 \times 10^{3}\;cal$

Thermodynamics

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Answer : (d) $\;5.9 \times 10^{3}\;cal$

Explanation :

Heat rejected during condensation of steam = $\;10 \times 540 = 5.4 \times 10^{3}\;cal$

Heat rejected during cooling = $\;10 \times 1 \times (100-50)$

$=0.5 \times 10^{3} \;cal$

Therefore , Total heat rejected per minute

$=5.9 \times 10^{3} \;cal$

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