$(a)\;5.4 \times 10^{3}\;cal\qquad(b)\;0.5 \times 10^{3}\;cal\qquad(c)\;4.9 \times 10^{3}\;cal\qquad(d)\;5.9 \times 10^{3}\;cal$

Thermodynamics

Want to ask us a question? Click here

Browse Questions

Thermodynamics

Ad |

0 votes

0 votes

Answer : (d) $\;5.9 \times 10^{3}\;cal$

Explanation :

Heat rejected during condensation of steam = $\;10 \times 540 = 5.4 \times 10^{3}\;cal$

Heat rejected during cooling = $\;10 \times 1 \times (100-50)$

$=0.5 \times 10^{3} \;cal$

Therefore , Total heat rejected per minute

$=5.9 \times 10^{3} \;cal$

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...