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The name of the following compound is : $4FeCl_3+3K_4Fe(CN)_6 \longrightarrow (x)+12KCl$

$(a)\;\text { Ferroynaide } \\(b)\;\text {Russian Blue}\\(c)\;\text {ferriode} \\(d)\;\text {Perssian Blue} $
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Perssian Blue is correct answer.
Hence d is the correct answer.
answered Mar 12, 2014 by meena.p
 
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