# The name of the following compound is : $4FeCl_3+3K_4Fe(CN)_6 \longrightarrow (x)+12KCl$

$(a)\;\text { Ferroynaide } \\(b)\;\text {Russian Blue}\\(c)\;\text {ferriode} \\(d)\;\text {Perssian Blue}$

Hence d is the correct answer.
answered Mar 12, 2014 by