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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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A heat engine operates between a cold reservoir at temperature $\;T_{1}=300 K\;$ & a hot reservoir at temperature $\;T_{2}=600 K\;$ . It takes 500 J heat from hot reservoir and delivers x J of heat to cold reservoir in a cycle . Then x = ?


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Answer : (b) $\;150$
Explanation :
Work done by engine = (500-x) J
Efficiency $\;\eta=\large\frac{(500-x)}{500}=1-\large\frac{\pi}{T_{2}}$
answered Mar 12, 2014 by yamini.v

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