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Three conducting rods of same material & area of cross - section are figured as shown . Then , $\;\large\frac{l_{1}}{l_{2}}=?$


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Answer : (c) $\;\large\frac{1}{6}$
Explanation :
Let the temperature of point O be
So , $\;\large\frac{(T_{A}-T_{O})}{l_{1}}=\large\frac{(T_{O}-T_{B})}{l_{2}}+\large\frac{(T_{O}-T_{C})}{l_{3}}$
answered Mar 12, 2014 by yamini.v

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