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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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Find the shortest distance between the lines $\large\frac{x-3}{1} = \frac{y-5}{-2} = \frac{z-7}{1}$$ \: and \: \large\frac{x+1}{7} = \frac{y+1}{-6} = \frac{z+1}{1}. $

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