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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Electromagnetic Induction

An aircraft having a wingspan of $20.48\; m$ flies due north at aspeed of $40 ms^{−1}$. If the vertical component of earth’s magneticfield at the place is $2 × 10^{−5}\; T$, Calculate the emf induced betweenthe ends of the wings.

(A) $- 0.0164 $volts

(B) $0.0164 $volts

(C)$- 0.0332 $volts

(D) $ 0.0184 $volts

1 Answer

Emf, $\varepsilon = -B l v = -2 \times 10^{-5} \times 20.8 \times 40$
Emf, $\varepsilon = - 0.0164$ volts
answered Mar 12, 2014 by balaji.thirumalai
 

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