(A) 1.22 V

(B) 3.67 V

(C) 4.9 V

(D) 2.45 V

Given $N = 5, r = 1.73m, B_1 = 2.18T, B_2 = 12.7 T, \theta = 27$

Induced emf $\varepsilon = \large\frac{d\Phi}{dt} = \large\frac{d NBA \cos \theta }{dt} =$$ NA\cos \theta $$\large\frac{B_2-B_1}{dt}$

$\varepsilon = 5 \times \pi \times 1.73^2 \times \cos 27 \times \large\frac{12.7-2.18}{180}$$ = 2.45V$

(d) option is correct.

Ask Question

Tag:MathPhyChemBioOther

Take Test

...