$(a)\;12.5 \;gm\qquad(b)\;25 \;gm\qquad(c)\;60 \;gm\qquad(d)\;0 \;gm$

Answer : (d) $\;0\;gm$

Explanation :

Heat required to bring ice to $\;0^{0}C$

$=60 \times 10 - (-5) \times 0.5$

$=150 \;cal$

Heat required to melt ice = $60 \times 80$

$=4800 cal$

Max heat that can be lost by water

$=100 \times 1 \times 50$

$=5000 cal$

Since the total heat needed to melt all ice can be lost by water , mass of ice left = 0 g

Ask Question

Tag:MathPhyChemBioOther

Take Test

...