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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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60 gm of ice at $\;-5^{0}C\;$ is mixed with 100 gm of water at $\;50^{0}C\;$. Latent heat of fusion = 80 cal/g , Specific heat of water = $\;1 cal/g^{0}C\;$ ,Specific heat of ice = $\;0.5 cal/g^{0}C$ . Then the mass of ice left in the mixture = ?

$(a)\;12.5 \;gm\qquad(b)\;25 \;gm\qquad(c)\;60 \;gm\qquad(d)\;0 \;gm$

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