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Formation of polythene from calcium carbide takes place as \[\] $ CaC_2+2H_2O \rightarrow Ca(OH)_2+C_2H_2$ \[\] $ C_2H_2+H_2 \rightarrow C_2H_4$ \[\] $ nC_2H_4 \rightarrow (- CH_2 - CH_2 -)n$ \[\] The amount of polythene obtained from 64.1 kg of $CaC_2$ is

$\begin {array} {1 1} (a)\;7 \: Kg & \quad (b)\;14 \: Kg \\ (c)\;21 \: Kg & \quad (d)\;28 \: Kg \end {array}$

 

1 Answer

Carbon is $ \large\frac{24}{64}$ of $CaC_2.\: Ca (40) + C_2 (24) = 64$. So carbon is $\large\frac{24}{64}$ of the $64\: kg = 24\: kg$. Carbon is $ \large\frac{12}{14}$ of polyethylene, formula $(CH_2)n = C (12) + H_2 (2) = 14$ (all times $n$). So if you have $24\: kg$ of carbon, that will make $24 \times \large\frac{14}{12} = 28\: kg$ of polyethylene.
Ans : (d)
answered Mar 12, 2014 by thanvigandhi_1
 
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