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# Formation of polythene from calcium carbide takes place as  $CaC_2+2H_2O \rightarrow Ca(OH)_2+C_2H_2$  $C_2H_2+H_2 \rightarrow C_2H_4$  $nC_2H_4 \rightarrow (- CH_2 - CH_2 -)n$  The amount of polythene obtained from 64.1 kg of $CaC_2$ is

$\begin {array} {1 1} (a)\;7 \: Kg & \quad (b)\;14 \: Kg \\ (c)\;21 \: Kg & \quad (d)\;28 \: Kg \end {array}$

Carbon is $\large\frac{24}{64}$ of $CaC_2.\: Ca (40) + C_2 (24) = 64$. So carbon is $\large\frac{24}{64}$ of the $64\: kg = 24\: kg$. Carbon is $\large\frac{12}{14}$ of polyethylene, formula $(CH_2)n = C (12) + H_2 (2) = 14$ (all times $n$). So if you have $24\: kg$ of carbon, that will make $24 \times \large\frac{14}{12} = 28\: kg$ of polyethylene.
Ans : (d)