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Corrosive sublimate is

$(a)\;HgCl_3 \\(b)\;Hg_2Cl_2 \\(c)\; Hg_2Cl \\(d)\;Hg_2Cl_3 $

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Corrosive sublimate is$HgCl_3 $
Hence a is the correct answer.
answered Mar 13, 2014 by meena.p
 
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