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What is the co-ordination number of the central metal ions in $[Mo(CN)_8]^{4-}$

$(a)\;8 \\(b)\;-8 \\(c)\;4 \\(d)\;-4 $

1 Answer

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$CN^{-}$ is a monodentate ligand .
Points of attachment $Mo^{4+}=8 \times 1=8$
$CN$ of $Mo^{++}=8$
Hence a is the correct answer.
answered Mar 13, 2014 by meena.p
 
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