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Catalyst required for the preparation of vinyl cyanide

$\begin{array}{1 1}(a)\;BaCN\\(b)\; NH_2OH\\(c)\;Ba(CN)_2\\(d)\;H_2SO_4\end{array}$

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Vinyl cyanide can be prepared by treating acetylene with HCN in the presence of $Ba(CN)_2$
$HC\equiv CH(\text{acetylene})+HCN\quad\underrightarrow{Ba(CN)_2}\quad H_2C=CH-CN$(vinyl cyanide)
Hence (c) is the correct answer.
answered Mar 13, 2014 by sreemathi.v
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