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An ideal Carnot heat engine operates on a temperature difference of $210$ degrees. One third of the heat absorbed from the source is discharged to the sink. If the work done per cycle is $400\; J$. Efficiency $(\eta)$ of an ideal can not heat engine is

$(a)\;0.52 \\(b)\;0.86 \\(c)\;0.66 \\(d)\;0.77$

Can you answer this question?

Efficiency $(\eta)$ of an ideal can not heat engine is $0.66$
Hence c is the correct answer.
answered Mar 13, 2014 by