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For an ideal gas

$(a)\;\bigg(\large\frac{\partial E}{\partial T} \bigg)_P=0 \\(b)\;\bigg(\large\frac{\partial E}{\partial V} \bigg)_T=0 \\(c)\;\bigg(\large\frac{\partial E}{\partial T} \bigg)_V=0\\(d)\;\bigg(\large\frac{\partial E}{\partial P} \bigg)_T=0 $

1 Answer

$\bigg(\large\frac{\partial E}{\partial V} \bigg)_T=0 $ is correct
Hence b is the correct answer.
answered Mar 13, 2014 by meena.p
 

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