logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
0 votes

The freezing point & boiling point of water are marked as $\;-20^{0}C\;$ & $\;180^{0}\;$ respectively . The thermometer will read human body temperature $\;(37^{0}C)\;$ as -

$(a)\;54^{0}\qquad(b)\;37^{0}\qquad(c)\;17^{0}\qquad(d)\;74^{0}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : $54^{0}$
Explanation :
Freezing point of water $\;=0^{0} C$
Freezing point of water $\;=100^{0}C$
Therefore , reading in thermometer for $\;37^{0}C = \large\frac{(180 - (-20))}{(100-0)} \times 37 + (-20)$
$= 54 ^{0}$
answered Mar 13, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...