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Chemical Thermodynamics
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The heat of neutralization is highest in
$(a)\;NH_4OH +HCl \\(b)\;NaOH + CH_3COOH \\(c)\;HCl+NaOH \\(d)\;CH_3COOH +NH_4OH $
jeemain
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Mar 13, 2014
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meena.p
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Jul 10, 2014
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1 Answer
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The heat of neutralization is highest in $HCl+NaOH$
Hence c is the correct answer.
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Mar 13, 2014
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meena.p
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