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The heat of neutralization is highest in

$(a)\;NH_4OH +HCl \\(b)\;NaOH + CH_3COOH \\(c)\;HCl+NaOH \\(d)\;CH_3COOH +NH_4OH $
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The heat of neutralization is highest in $HCl+NaOH$
Hence c is the correct answer.
answered Mar 13, 2014 by meena.p
 

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