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Calculate the enthalpy change when $50\; ml$ of $0.01\; M Ca(OH)_2$ reacts with $25\; ml$ of $0.01 \;M HCl.$ Given that $\Delta H^0_{neut}$ of a strong acid and strong base is $140$ cal/ equivalent

$(a)\;14.0\;cal \\(b)\; 35\;cal\\(c)\;10.0\;cal \\(d)\;7.5\;cal $

1 Answer

The enthalpy change is 35 cal
$ 35\;cal$ is correct.
Hence b is the correct answer.
answered Mar 13, 2014 by meena.p
edited Mar 6 by sharmaaparna1

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