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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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For a gaseous reaction $2A_2(g) + 5B_2(g) \rightarrow 2A_2B_5(g)$ at $ 27^{\circ}C$ the heat change at constant pressure is found to be $-50160\: J$. Calculate the value of internal energy change $(\Delta U). (R = 8.314 \: J/K\: mol)$

$\begin {array} {1 1} (a)\;37689\: J & \quad (b)\;-37689 \: J \\ (c)\;62631 \: J & \quad (d)\;-62631 \: J \end {array}$

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