$(a)\;degrees\;of\;freedom\;of\;gas\qquad(b)\;temperature\;change\;value\qquad(c)\;no .\; of \;moles\;of\;gas\qquad(d)\; All\;of\;these$

Thermodynamics

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Answer : degrees of freedom of gas

Explanation :

$\bigtriangleup Q = n C_{p} \bigtriangleup T$

$\bigtriangleup u = n C_{v} \bigtriangleup T$

$\bigtriangleup W = n C_{p} \bigtriangleup T$

$\bigtriangleup Q : \bigtriangleup u : \bigtriangleup W$

$= C_{p} : C_{v} : C_{p} - C_{v}$

$=\large\frac{(f+1)}{2} R : \large\frac{fR}{2} : R$

$(f+1) : f : 2$

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