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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

The equilibrium constant for a reaction\[\] $CO_2(g) + H_2(g) \rightleftharpoons CO(g) + H_2O(g) \: is \: 73$.\[\] Calculate the value of standard free energy change.

$\begin {array} {1 1} (a)\;1063.17\: J/mol & \quad (b)\;-1063.17 \: J/mol \\ (c)\;10.632 \: kJ/mol & \quad (d)\;-10.632 \: kJ/mol \end {array}$

1 Answer

$ \Delta G^o = -2.303RT\: log \: K$
$ = -2.303 \times (8.314 \: J/Kmol)(298 \: K)(log\: 73)$
$ = -2.303 \times 8.314 \times 298 \times 1.8633 = -10.632\: kJ/mol$
Ans : (d)
answered Mar 13, 2014 by thanvigandhi_1
 

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