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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Communication Systems
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The maximum distance upto which TV transmission from a TV tower of height 'h' can be received is proportional to

$\begin{array}{1 1}(a)\;h^{\Large\frac{1}{2}}&(b)\; h\\(c)\;h^{\Large\frac{3}{2}}&(d)\;h^2\end{array}$

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The maximum distance upto transmission is received is proportional to $h^{\Large\frac{1}{2}}$.
Hence (a) is the correct answer.
answered Mar 14, 2014 by sreemathi.v

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