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Figure shows the arrangement , gas is thermally insulated . Having pressure $\;p_{g}\;$ ( greater than atmospheric pressure $\;p_{a}\;$ ) . Spring of force constant k is initially unstretched . Position of mass m & area S is friction less and in equilibrium position , it rises up a distance $\;x_{0}\;$ , then -


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Answer : $\;final\;pressure=p_{a}+\large\frac{kx_{0}}{S}+\large\frac{mg}{S}$
Explanation :
FBD of pistern in equation m position
$pS=p_{a} S + mg +kx_{0}$
answered Mar 15, 2014 by yamini.v
edited Mar 15, 2014 by yamini.v

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