logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

If a system absorbs reversibly 600 J of heat and performs 250 J of work, the increase in internal energy of the system is

$\begin {array} {1 1} (A)\;850\: J & \quad (B)\;350\: J \\ (C)\;250\: J & \quad (D)\;600\: J \end {array}$

Download clay6 mobile app

1 Answer

$ \Delta U = 600-250 = 350\: J$
Ans : (B)
answered Mar 15, 2014 by thanvigandhi_1
 

Related questions

...