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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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The enthalpy of formation of $ Cl(g)\: is\: x\: kJ/mol$. The value of $ \Delta H_{Cl-Cl} $ will be

$\begin {array} {1 1} (A)\;x \: kJ/mol & \quad (B)\;2x\: kJ/mol \\ (C)\;\large\frac{x}{2}\: kJ/mol & \quad (D)\;can’t \: be \: determined \end {array}$

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$Cl-Cl(g) \rightarrow 2Cl(g);\: \: \: \: \Delta H = 2 \Delta H_fCl – 0 = 2x\: kJ/mol$
Ans : (B)
answered Mar 15, 2014 by thanvigandhi_1
 

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