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Thermodynamics

# The enthalpy of formation of $Cl(g)\: is\: x\: kJ/mol$. The value of $\Delta H_{Cl-Cl}$ will be

$\begin {array} {1 1} (A)\;x \: kJ/mol & \quad (B)\;2x\: kJ/mol \\ (C)\;\large\frac{x}{2}\: kJ/mol & \quad (D)\;can’t \: be \: determined \end {array}$

$Cl-Cl(g) \rightarrow 2Cl(g);\: \: \: \: \Delta H = 2 \Delta H_fCl – 0 = 2x\: kJ/mol$
Ans : (B)