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Among the following elements, the one having the highest ionization energy is


$(A)\;[Ne] 3s^2p^1$
$(B)\;[Ne] 3s^2p^3$
$(C)\;[Ne] 3s^2p^2$
$(D)\;[Ar] 3d^{10}\;4s^2\;4p^3$

1 Answer

The element with $[Ne] 3s^2p^3$, because IE increases in a period from left to right. Moreover this element has half-filled p-electrons
answered Mar 16, 2014 by balaji.thirumalai
 

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