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The ionization enthalpy of hydrogen atom is $1.312 \times 10^{6} \; J/mol$. The energy required to excite the electron in the the atom from $n=1 \rightarrow n = 2$ is:

\begin{matrix} (A)\; 8.51 \times 10^5 \; J/mol \\ (B)\; 6.56 \times 10^5 \; J/mol \\ (C)\; 7.56 \times 10^5 \; J/mol \\ (D)\; 9.84 \times 10^5 \; J/mol \end{matrix}

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Ans: $(D)\; 9.84 \times 10^5 \; J/mol $
$\Delta E = E_2 - E_1 = -\large\frac{1.312 \times 10^6}{2^2} - $$ \large\frac{-1.312 \times 10^6}{1^2}$$ = (-0.328 + 1.312) \times 10^6$
$\Delta E = 9.84 \times 10^5 \; J/mol$
answered Mar 16, 2014 by balaji.thirumalai
 

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