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In Zeigler-Natta polymerisation of ethylene the active species is


(a) $AlCl_3$
(b) $Et_3Al$
(c) $CH_2CH_2$
(d) $Ti^{3+}$

Can you answer this question?
 
 

1 Answer

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Answer: $Ti^{3+}$
$Ti^{3+}$ species from $TiCl_3$ compound having active site vacant which accomodate one alkyl group.
answered Mar 16, 2014 by mosymeow_1
 
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