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In Zeigler-Natta polymerisation of ethylene the active species is

(a) $AlCl_3$
(b) $Et_3Al$
(c) $CH_2CH_2$
(d) $Ti^{3+}$

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Answer: $Ti^{3+}$
$Ti^{3+}$ species from $TiCl_3$ compound having active site vacant which accomodate one alkyl group.
answered Mar 16, 2014 by mosymeow_1
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