logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Communication Systems

Amplitude of carrier wave is 20v amplitude of signal is 2v.Percentage of modulation is

$\begin{array}{1 1}(a)\;\text{20 %}\\(b)\; \text{10 %}\\(c)\;\text{100 %}\\(d)\;\text{80 %}\end{array}$

1 Answer

$m=\large\frac{E_s}{E_c}=\frac{2}{20}=\frac{1}{10}$
% of modulation =$\large\frac{1}{10}$$\times 100$
$\Rightarrow 10\%$
Hence (b) is the corrret option.
answered Mar 17, 2014 by sreemathi.v
 

Related questions

...