$\begin{array}{1 1}(a)\;0.3\\(b)\;3\\(c)\;0.6\\(d)\;6\end{array}$

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Maximum voltage of AM wave $V_{max}=\large\frac{10}{2}$$=5mv$

Minimum voltage of AM wave $V_{min}=\large\frac{2}{2}$$=1mv$

Modulating factor =$\large\frac{V_{max}-V_{min}}{V_{max}+V_{min}}$

$\Rightarrow \large\frac{5-1}{5+1}$

$\Rightarrow \large\frac{4}{6}$

$\Rightarrow 0.6$

Hence (c) is the correct option.

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