# Calculate the value of equilibrium constant for a reaction at 400K  $2NOCl(g)2NO(g) + Cl(g)$  $\Delta S$ and $\Delta H$ are 122 J/Kmol and 77.2 kJ/mol respectively.

$\begin {array} {1 1} (A)\;1.96 \times 10^{-4} & \quad (B)\;19.6 \times 10^{-4} \\ (C)\;19.6 \times 10^{-2} & \quad (D)\;1.96 \times 10^{-2} \end {array}$

## 1 Answer

$\Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ} = 77200\: – 400(122) = 28400\: J/mol$
$\Delta G^{\circ}= -2.303\: RT \: log \: K$

1 answer

1 answer

1 answer

1 answer

1 answer

1 answer

1 answer