Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The number of moles of lead nitrate needed to coagulate 2 mol of colloidal $[AgI]I^-$ is

(a) 2
(b) 1
(c) 1/2
(d) 2/3
Can you answer this question?

1 Answer

0 votes
Answer: 1
$2[AgI]I^- + Pb^{2+} \longrightarrow PbI_2 + 2AgI$
Thus, 2 moles of $[AgI]I^-$ are coagulated by 1 mole of $Pb^{2+}$ i.e., 1 mole of $Pb(NO_3)_2$.
answered Mar 17, 2014 by mosymeow_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App