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The number of moles of lead nitrate needed to coagulate 2 mol of colloidal $[AgI]I^-$ is


(a) 2
(b) 1
(c) 1/2
(d) 2/3
Can you answer this question?
 
 

1 Answer

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Answer: 1
$2[AgI]I^- + Pb^{2+} \longrightarrow PbI_2 + 2AgI$
Thus, 2 moles of $[AgI]I^-$ are coagulated by 1 mole of $Pb^{2+}$ i.e., 1 mole of $Pb(NO_3)_2$.
answered Mar 17, 2014 by mosymeow_1
 

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