(a) 1/n

(b) log k

(c) -log k

(d) n

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Answer: 1/n

For the adsorption of a gas on a solid $\frac{x}{m} = kp^{1/n}$ This equation is known as Freundlich Adsorption Isotherm.

On taking logarithm on both sides, we obtain,

$\Longrightarrow log \frac{x}{m} = log k + \frac{1}{n} log p$

$\therefore$ plot of log x/m versus log p will be linear with slope = 1/n .

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