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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
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The reaction conditions leading to the best yields of $C_2H_5Cl$ are

$\begin{array}{1 1}(a)\;C_2H_6(excess)+Cl_2\quad\underrightarrow {\text{UV light}}\\(b)\;C_2H_6+Cl_2\quad\underrightarrow {\text{dark}}\\(c)\;C_2H_6+Cl_2(excess)\quad\underrightarrow {\text{UV light}}\\(d)\;C_2H_6+Cl_2\quad\underrightarrow {\text{UV light}}\end{array}$

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Chlorination beyond monochlorination in the preparation of alkyl halides in presence of ultraviolet light is suppressed if excess alkane is used.
$C_2H_6(excess)+Cl_2\quad\underrightarrow{\text{UV light}}\quad C_2H_5Cl$
Hence (a) is the correct option.
answered Mar 18, 2014 by sreemathi.v

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