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In the presence of peroxide,hydrogen chloride and hydrogen iodide do not give anti-Markownikoff addition to alkenes because

$\begin{array}{1 1}(a)\;\text{Both are highly ionic}\\(b)\; \text{One is oxidising and the other is reducing}\\(c)\;\text{One of the steps is endothermic in both the cases}\\(d)\;\text{All the steps are exothermic in both the cases}\end{array}$

1 Answer

Because one of the steps is endothermic in both cases.
Step I:
Step II:
For HCl step I(b) is endothermic and step II is exothermic.
For HI step I(b) is exothermic and step II is endothermic.
Hence (c) is the correct option.
answered Mar 18, 2014 by sreemathi.v
 

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