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The reaction of propene with HOCl proceeds via the addition of

$\begin{array}{1 1}(a)\;H^+\text{ in the first step}\\(b)\; Cl^+\text{ in the first step}\\(c)\;OH^-\text{ in the first step}\\(d)\;Cl^+\;and\;OH^-\text{ in a single step}\end{array}$

2 Answers

Alkenes undergo electrophilic addition reactions.HOCl on self ionisation produces $Cl^+$ which attacks first.
$HOCl+HOCl\rightarrow H_2O+OCl^-+Cl^+$
$\therefore$ The option is (b) $Cl^+$ in the first step.
answered Mar 18, 2014 by sreemathi.v
B is correct
answered May 26, 2017 by navya291197