# On monochlorination of 2-methylbutane,the total number of chiral compounds formed is

$\begin{array}{1 1}(a)\;2\\(b)\;4\\(c)\;6\\(d)\;8\end{array}$

Chlorination at C-2 and C-4 produces no chiral compound.
Hence (b) is the correct answer.
It is 4 because we are counting both the products enantiomers also??