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On monochlorination of 2-methylbutane,the total number of chiral compounds formed is

$\begin{array}{1 1}(a)\;2\\(b)\;4\\(c)\;6\\(d)\;8\end{array}$

1 Answer

Chlorination at C-2 and C-4 produces no chiral compound.
Hence (b) is the correct answer.
answered Mar 18, 2014 by sreemathi.v
It is 4 because we are counting both the products enantiomers also??

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