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When phenyl magnesium bromide reacts with t-butanol the product would be

$\begin{array}{1 1}(a)\;\text{benzene}\\(b)\; \text{phenol}\\(c)\;\text{t-butyl benzene}\\(d)\;\text{t-butyl phenyl ether}\end{array}$

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1 Answer

Grignard reagent reacts with compounds containing active hydrogen to form hydrocarbons corresponding to alkyl(or aryl) part of the reagent.
$C_6H_5MgBr+Me_3COH\rightarrow C_6H_6+Me_3COMgBr$
Hence (a) is the correct option.
answered Mar 18, 2014 by sreemathi.v
 

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