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In Zeigler-Natta polymerization of ethylene the active spices is

$(a)\;Alcl_{3}\qquad(b)\;El^{-}_{3}Al\qquad(c)\;CH_{2}CH_{2}\qquad(d)\;Ti^{3+}$

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Answer : $\;Ti^{3+}$
Explanation :
$Ti^{3+}\;$ Species from $\;Ticl_{3}\;$ compound having active site vacant which accomodates one alkyl group .
answered Mar 18, 2014 by yamini.v
 
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