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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
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Hydrogenation of the below compound is the presence of poisoned palladium catalyst gives

$\begin{array}{1 1}(a)\;\text{an optically active compound}\\(b)\; \text{an optically inactive compound}\\(c)\;\text{a racemic mixture}\\(d)\;\text{a diastereomeric mixture}\end{array}$

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addition of a triple bond occurs by syn-addition of hydrogen.The configuration of double bond already present is cis.The compound formed will have a plane symmetry and thus it will be optically inactive.
Hence (b) is the correct option.
answered Mar 18, 2014 by sreemathi.v

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