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# The nodal plane in the $\pi$-bond of ethene is located in

$\begin{array}{1 1}(a)\;\text{the molecular plane}\\(b)\; \text{a plane parallel to the molecular plane}\\(c)\;\text{a plane perpendicular to the molecular plane which bisects the carbon-carbon }\sigma-\text{bond at right angle}\\(d)\;\text{a plane perpendicular to the molecular plane which contains the carbon-carbon }\sigma-bond\end{array}$

Formation of a $\pi$-bond occurs by the sideways overlap of p-orbitals of two C-atoms.The molecular plane does not have any $\pi$-electron density since the p-orbitals are perpendicular to the plane containing the ethene molecule.The nodal plane in the $\pi$-bond of ethene is located in the molecular plane.
Hence (a) is the correct option.