$V=30.0$

$I=0.020\;A$

$R=\large\frac{V}{I}=\frac{30}{0.020}$

$\quad= 1.50\;R \Omega$

Error $=R=\large\frac{V}{I}$

$\large\frac{\Delta R}{R}=\frac{\Delta V}{V}+\frac{\Delta I}{I}$

$\Delta R=R \bigg(\large\frac{\Delta V}{V} +\frac{\Delta I}{I} \bigg)$

$\qquad= 1.50 \times 10^3 \bigg (\large\frac{0.1}{30.0}+\frac{0.001}{0.020} \bigg)$

$\qquad= 0.080\;k \Omega$

Hence d is the correct answer.